Amarine biologist collects data on the length of rainbow trout on a protected western river. she finds that the length of adult trout in her study are approximately normally distributed with mean 14 inches. she also reports that the minimum length was 10 inches and the maximum was 18 inches. based on this information what is the most likely value of the standard deviation?

The standard deviation of the data is 2 inches.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14

We are given that the distribution of  length of adult trout is a bell shaped distribution that is a normal distribution.

Minimum length = 10 inches

Maximum length = 18 inches

Range

= Maximum length - Minimum length = 18 - 10 = 8

Thumb Rule of Standard Deviation:

Thus, by thumb rule, we get,

Thus, the standard deviation of the data is 2 inches.

add an image

step-by-step explanation:

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

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